A person travels on a semi-circular track of radius 500m during a morning walk. If he starts from one end of the track and reaches the other end. Calculate the distance travelled and the magnitude of the displacement of the person.
Answers
Answered by
5
Explanation:
ANSWER
d= 500 m
(2πr)
circumference
=
2π
(
2
500
)
speed
=
500π
min
m
distance
=
500π
min
m
×
5.5 min
= 2750π m
= 8635 m
Displacement
500π is one round
2750π is
→
?
500π
2750π
=
5.5 rounds
displacement = length of diameter
=
500 m
Answered by
3
Answer:
Given:
Radius, r = 40 m
Distance = πr = begin mathsize 14px style 22 over 7 cross times 40 space straight m equals 125.7 space straight m end style
The distance travelled by the person is 125.7 m.
Displacement is distance between final and initial points which is the diameter.
Displacement = 2×r = 2×40 m = 80 m
The magnitude of displacement of person is 80 m.
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