A person travels one-third of the total distance at a speed of 2 km/h, the next one third of the total distance at a speed of 3 km/h and the rest of the total distance at a speed of 6 km/h. Find the aver- age speed of the person for the total trip
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Answer:
The time taken by the boy to cover a certain distance = 1 hour 24 minutes
The speed of covering two-thirds distance = 4 km/h
The speed of covering the rest of the distance = 5 km/h
Formula used:
T = D/S
where, T = time of the journey, S = speed, D = distance travelled
Calculation:
Let the total distance be 3D km.
The two-third distance of 3D = (2/3) × 3D = 2D km
Remaining distance
The One-third distance of 3D = (1/3) × 3D = D km
Time taken for covering 2D distance = (2D/4) hour
Time taken for covering rest distance = (D/5) hour
According to the question,
(2D/4) + (D/5) = 1 h 24 min
⇒ (D/2) + (D/5) = 1 + (24/60)
⇒ (5D + 2D)/10 = 1 + (2/5)
⇒ 7D/10 = 7/5
⇒ D/2 = 1
⇒ D = 2 km.
Now, total distance = 3 × 2 = 6 km
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