A person using 50 cm long handle spanner can open a nut by applying 150 N force. What will be the moment of force of the spanner?
Answers
Answered by
170
Answer:
- 75 Newton is the required moment of force.
Explanation:
According to the Question
It is given that ,
- Magnitude of Applied Force ,F = 150N
- Perpendicular Distance = 50cm
we have to calculate the moment of force .
As we know that Moment of Force is calculated by the product of Force and its perpendicular distance.
Firstly we change the unit here
Conversion of Unit :
↠ Perpendicular Distance = 50/100 m
↠ Perpendicular Distance = 0.5m
Now, calculating the Moment of Force by using Formula.
- Moment of Force = Force×Perpendicular distance
by putting the value we get
↠ Moment of Force = 150×0.5
↠ Moment of Force = 15×5
↠ Moment of Force = 75N
- Hence, the moment of force will be 75 Newton.
Answered by
153
- ➬ Length of spanner = 50 cm
- ➬ Force applied to open the nut = 150 N
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
- ➬ What is the moment of force = ?
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
❒ Formula Used :
Moment of force :
❒ Requird Converting :
1 m = 100 cm. Hence,
❒ Finding the moment of force :
❒ Therefore :
❝ Moment of force on the nut is 75 N. ❞
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