Question

A person using a 60 cm long handled spanner can open a nut by applying a 120 Newton force. What should be the length of the handle if you want to open the nut by applying a force of 80 Newton?A. 45cm B. 90cm C. 60cm D. 72cm​

Answer 1

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{question:}}}}}}}\end{gathered}$

A person using a 60 cm long handled spanner can open a nut by applying a 120 Newton force. What should be the length of the handle if you want to open the nut by applying a force of 80 Newton ??

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Given:}}}}}}}\end{gathered}$

• $\red\bigstar$ F1 = 120n force
• $\red\bigstar$ D1 = 60cm
• $\red\bigstar$ f2 = 80n

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{to find:}}}}}}}\end{gathered}$

• $\red\bigstar$ d2

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{formula:}}}}}}}\end{gathered}$

• by using principal of moment formula ⟼f1 D1 = f2 d2

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{solution:}}}}}}}\end{gathered}$

now by using formula F1 D1 = f2 d2

now, by putting values we get,

$\rm :\longmapsto\:120 \times 60 = 80 \: d_{2}$

$\rm :\longmapsto\: d_{2} = \frac{120 \times 60}{80}$

$\rm :\longmapsto\: \cancel \frac{120 \times 60}{80 }$

$\rm :\longmapsto\: d_{2} = 90cm$

so therefore d2 = 90cm