Question

A person walks 1.5 m/s for 10 min heading west. He then turns and walks for 6.0 min heading east. What is his average speed and velocity?

Answer 1

Step-by-step explanation:

First towards west 10 min.

and then walk towards east 6 min.

Now, his speed is 1.5 m/sec it means

1 second=1.5 meter

and we know,

60 second = 1 minute

then distance in 10min.=10×60=600 second=600×1.5=900 m

and distance in 6 min=6×60=360 m

then, AVG distance= (total distance)/ total time

=(900+360)/(10+6)

=1260/16

=78.75 m/sec