Question

A person walks 12.0∘ north of west for 55.0m and 63.0∘ south of west for 25.0m. What is the magnitude of his displacement? Solve analytically.
a. 10.84m
b. 65.1m
c. 66.04m
d. 80.00m

Help plz. Please don't answer this just to get B point. Someone save meeee. This is highschool physics. I'm learning abt Motion in Two Dimensions from openstax. I'll give u 20p.

Answer 1

Answer:

28. A person walks 12.0"north of west for 55.0 m and 63.0' south of west for 25.0m. What is the magnitude of his displacement? Solve analytically. a. 10.84 m b. 65.1 m C. 66.04 m d. 80.00 m

Answer 2

Answer:

We need to use the technique of vector addition to calculate the extent of the person's motion. We can decompose the movement of the individual into two separate vectors, one heading 12.0 degrees north of west and another pointing 63.0 degrees south of west.

Explanation:

First, let's transform the angles into the direction vectors corresponding to them. We may use a notation known as the unit vector to describe the directions. A vector's direction is represented by a unit vector with a magnitude of one and the same name.

It is possible to write the following as the direction vector for 12.0 degrees north of west:

v1 = (-cos (12.0), sin (12.0))

Similarly, the direction vector for 63.0 degrees to the west or south may be expressed as:

v2 = (-cos (63.0), -sin (63.0))

Now that we have added the two vectors together, we can determine the magnitude of the displacement by taking the magnitude of the vector created as a consequence of the addition.

To discover the components of each vector so that we may add them together, we must first multiply each vector's magnitudes by the associated direction vector. The following items make up the first vector's components:

(55.0 m) v1 = (-54.05 m, 10.78 m)

The following items make up the components of the second vector:

(25.0 m) v2 = (-11.25 m, -22.33 m)

Now that we have the individual components, we can sum them together to obtain the overall displacement:

(-54.05 m, 10.78 m) + (-11.25 m, -22.33 m) = (-65.30 m, -11.55 m)

This vector's magnitude is represented as:

| (-6.30 m, -11.55 m) | = sqrt [(-65.30) ^2 + (-11.55) ^2] = 66.04 m

As a result, the distance that the guy has moved is equal to 66.04 meters, and the correct response is (c).

To learn more about vector addition, click on the given link.

https://brainly.in/question/23884867

To learn more about motion, click on the given link.

https://brainly.in/question/10642866

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