Question

A person walks 15 km towards north and turns left walks 10 km and turns right walks 15 km and turns right walks 17 km. Then find the distance he is from the starting point and in which direction he is from the starting point?
a. 10 km, west
b. 27 km, west
c. 10 km, East
d. 10 km, south ​

Answer 1

Answer:

The distance is 30.80 from the starting point and in which direction he is from the starting point in East direction.

Step-by-step explanation:

As per the data given in the question

we have to calculate

the distance he is from the starting point and in which direction he is from the starting point.

As per the question

It is given that

A person walks 15 km towards north and turns left walks 10 km and turns right walks 15 km and turns right walks 17 km.

Lets assume that From point A a person walks 15 km towards north to reach at point B and turns left walks 10 km to reach at point C and turns right walks 15 km to reach at point D and turns right walks 17 km to reach at point E.

then we have to calculate distance AE by pythagoras theorem.

AE^2=(Vertical distance between AE)^2 +(Horizontal distance between AE)^2

⇒AE^2 = (17-10)^2+(15+15)^2

⇒AE=$\sqrt{7^{2}+30^{2} }$

⇒AE= 30.80 East

Hence,the distance is 30.80 from the starting point and in which direction he is from the starting point in East direction.

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Answer 2

The answer is approx 31 km and the direction is east

Step-by-step explanation:

According to the question,

Now we prepare a figure,

$(AF)^2=(AE)^2+(EF)^2\\(AF)^=(30)^2+(7)^2\\(AF)^2=900+49\\(AF)^2=949\\AF=30.84\\AF=31(Approx)$

And Endpoint on East.

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