Question

A person walks 3 km from point “P” towards east and reaches point “Q” and then walks 4 km north to reach point “R”. What is the minimum distance between P and R

Answer 1

Answer:

5 km

Step-by-step explanation:

starting point P

distance from P to Q = 3km

distance from Q to R = 4km

join P and R

we get a right angle triangle PQR

where PR become the hypotenuse

apply Pythagoras theorem

${pr}^{2} = {pq}^{2} + {qr}^{2} \\ {pr}^{2} = {3}^{2} + {4}^{2} \\ {pr}^{2} = 9 + 16 \\ {pr}^{2} = 25 \\ pr = \sqrt{25} \\ pr = 5$

therefore the distance between PR is 5km

hope you get your answer

Answer 2

Given,

Distance between PQ = 3km

Distance between QR = 4km

To Find,

Distance between PR =?

Solution,

A person walks toward east then walks toward north which means he took a left turn at a 90° angle.

∠PQR = 90°

PQR is a right-angled triangle and PR is the hypotenuse.

By Pythagoras theorem,

$(PR)^2 = (PQ)^2 +(QR)^2 \\(PR)^2 = (3)^2 +(4)^2 \\(PR)^2 = 9 + 16 \\(PR)^2 = 25\\PR = \sqrt{25} \\PR = 5km$

Hence, the distance between PR is 5 km