A person walks 4 km towards west, then turns to his right to travel 9 km. He turns towards east and travels 12 km. Finally, he travels 3 km towards south. How far is he from the initial position (in km)?
Answers
Answered by
1
Step-by-step explanation:
sorry yaar i don't have any idea about this question
Answered by
5
The total distance covered by man is 28 km
Step-by-step explanation:
Use Pythagoras to get displacement
x = \sqrt{ {6}^{2} + {8}^{2} } = \sqrt{100} = 10x=
6^(2) +8 ^(2) = 100 =10
So he is in North-East , 10 m .
Your Answer
The total distance traveled by the person is 28 kms.
The direction of the person with respect to his initial position is north-east.
And the displacement of the person from his initial position is 10 kms.
So, the person is 10 kms away from his initial position actually.
Similar questions