A person walks 4 km, turns towards his left and walked 6 km, then tums to his right again and walked 4 km. The displacement from the starting
point is -
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The ans is in the jpg file given below(10km)
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Given:
A person walks 4 km, turns towards his left and walked 6 km, then tums to his right again and walked 4 km.
To find:
The displacement of the object
Solution:
As from the figure you can see that the triangles formed are similar to each other.
And one of the sides of the triangle is 4 centimeters.
So by the similarity rule, the line DC must bisect the line AB
So the length of AE must be 3 cm
Now,
in any of the triangle using the Pythagoras theorem
ΔADE
AD²+AE² = DE²
- 4²+3² = DE²
- DE² = 16+9
- DE = √25
- DE = 5 cm
And the displacement is
- DC = 2DE
- DC = 2×5 cm
- DC = 10 cm
So the displacement of the body is 10 cm
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