Question

A person walks 60 m in 1 minute. Then he walks another in 30 m in 2 minutes. What is the average speed

of the person?​

Answer 1

Answer:

Average speed of the person = 0.5 m/s

Explanation:

As per the provided information in the given question, we have :

• In first 1 minute, a person walks 60 m.
• In another 2 minutes, he walks 30 m.

We are asked to calculate average speed of the person.

We'll be using average speed formula in order other calculate is calculate speed.

$\\ \longrightarrow \quad\pmb{\boxed{ \sf {Speed_{(avg) } = \dfrac{Total \; Distance}{Total \; Time} }}}$

★ Calculating total distance :

$\\ \longrightarrow \quad \sf { Total \; distance = 60 \; m + 30 \; m}$

$\\ \longrightarrow \quad \bf\underline { Total \; distance = 90 \; m}$

★ Calculating total time :

$\\ \longrightarrow \quad \sf { Total \; time = 1 \; minute + 2\; minutes}$

• 1 minute = 60 seconds

$\\ \longrightarrow \quad \sf { Total \; time = 60\; seconds + (2 \times 60)\; seconds}$

$\\ \longrightarrow \quad \sf { Total \; time = 60\; seconds + 120\; seconds}$

$\\ \longrightarrow \quad \bf\underline { Total \; time = 180 \; seconds}$

Now, substituting the values in the formula of average speed,

$\\ \longrightarrow \quad\pmb{\boxed{ \sf {Speed_{(avg) } = \dfrac{Total \; Distance}{Total \; Time} }}}$

$\\ \longrightarrow \quad \sf {Speed_{(avg) } = \dfrac{90 \; m}{180 \; s} }$

$\\ \longrightarrow \quad \sf {Speed_{(avg) } = \dfrac{9 \; m}{18 \; s} }$

$\\ \longrightarrow \quad \sf {Speed_{(avg) } = \dfrac{1 \; m}{2 \; s} }$

$\\ \longrightarrow \quad \bf \underline{Speed_{(avg) }= 0.5 \; m/s}$

Therefore, average speed of the person is 0.5 m/s.