Question

A person walks a distance in 114 days, when he
rests 9 hours a day. How long will he take to walk
twice the distance if he walks twice as fast and rests
twice as long each day as before?​

Answer 1

Answer:

Step-by-step explanation:

Let the initial distance be x kms

Rest= 9 hrs

Total walking hrs in a day= 24–9=15

Total time in hrs= 114*15hrs

Let the speed be y km/hr

We know that

Speed *time= distance

y*114*15=x

y= x/114*15 - - - - - - equation 1

New speed= 2y

Rest= 2*9=18hrs

Total walking hrs in a day= 6

Total time in hrs= 6*days

New distance=2x

Again,

Speed*time= distance

2y*days*6= 2x

y*days*6=x

days=x/y*6——————-equation 2

From eq 1 in eq 2

days= x/x*6/114*15

days=114*15/6

days=57*5

days=285