A person walks along a circular path of radius r from a to b as shown in the figure . displacement transversed by the person as
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Hello mate,
● Answer-
s = √3r
● Explaination-
From the figure, the angle of arc AOB is
θ = 180-60
θ = 120°
In ∆AOB, OA = OB = r
Therefore, ∆AOB is isosceles angle triangle.
Length of the base of isosceles angled triangle is calculated by-
s = 2r.sin(θ/2)
s = 2r.sin(120/2)
s = 2r.sin(60)
s = 2r.(√3/2)
s = √3 r
Therefore, displacement of the man is √3r.
Hope it helps...
● Answer-
s = √3r
● Explaination-
From the figure, the angle of arc AOB is
θ = 180-60
θ = 120°
In ∆AOB, OA = OB = r
Therefore, ∆AOB is isosceles angle triangle.
Length of the base of isosceles angled triangle is calculated by-
s = 2r.sin(θ/2)
s = 2r.sin(120/2)
s = 2r.sin(60)
s = 2r.(√3/2)
s = √3 r
Therefore, displacement of the man is √3r.
Hope it helps...
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