Question

A person walks along the sides of a square field each side is 100m long. What is the maximum magnitude of displacement of the person in any time interval?

Answer 1

The maximum displacement is the diagonal of the square field.

side of square = 100m
diagonal = √100² + 100² = √20000 = 100√2 m = 141.42m

So maximum displacement is 141.42m.

Answer 2

The maximum ‘magnitude of displacement’ of the ‘person in any time interval’ is 141.42 m.

Given:

A person ‘walks along’ the “sides of a square field” each side is “100m long”.

Then find the maximum ‘magnitude of displacement’ of the person in ‘any time interval’.

Solution:

The maximum displacement is equal to the diagonal of the ‘square field’.

Side of a square, a = 100 m.

Diagonal of the square $=\sqrt{2 a}$

$=\sqrt{2 \times 100 \times 100}$

$=100 \sqrt{2}$

$=100 \times 1.414=141.42\ m$

So maximum displacement is 141.42 m.