Question

A person walks at 5 kmph, and reaches his destination 10 minutes late. If he increases his speed by 1
kmph., he would have reached 15 minutes earlier. The distance he travelled from his house is?​

Answer 1

Answer:

12.5 Km

Explanation:

Let 't' be the time he takes to reach destination and 'd' be the distance.

ATQ:

d=5*(t+1/6)=6*(t-1/4)

t=5/6+6/4=7/3.

Now, d=5*(7/3+1/6)=12.5 Km

Answer 2

Answer:

Explanation:

Step-by-step explanation:

Lets solve this using ratio :  

Since the distance is constant ,since dist = speed x time

if ratio of speed is 5:6 therefore ratio of time will be 6:5(dist is const)

difference in time (6-5)parts = 1 part = 25/60 hr that implies

5 parts(taking from ratio of time 6:5) is (5x25)/60 hr

so distance = (6 x 125)/60 =12.5 kms