Question

A person walks at the speed of 6 km/hr along
a square path shown. The side of the square
is 18 km. He starts from position O, the mid-
point of side AD, in the direction shown. He
reaches point F, the midpoint of side CD. The
average velocity of the person is
(1) 6 km/hr west-south
(2) v2 km/hr south-west
(3) 9 km/hr south-west
(4) 312 km/hr west-south​ ((
(please answer with explanation)))

Answer 1

Answer:

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▪Enolase was broad substrate specificity.

▫Enolase also called 2-phospho -

Answer 2

Answer:

V=3√2 km/hr ( North east direction)

Explanation:

Given that speed of the person ,v= 6 km/hr

The distance OD= 9 km

The time taken to cover the 9 km

t= OD/v

t= 9 /6 = 1.5 hr

Time taken to cover DF ,t=1.5 hr

We know that

Total displacement = Average velocity x Total time

Displacement OF

OF²=9²+9²

OF=9√2 km

OF = V x ( t+ t)

9√2 = V( 1.5 +1.5 )

V=3√2 km/hr ( North east direction)