Question

A person walks from his home to a supermarket at a distance of 1 km in 0.4 hours.
He then returns to his home in a time of 0.6 hours. Find the average speed of the
boy.

Answer 1

Answer:

$\boxed{\mathfrak{Average \ speed \ (v_{avg})= 2 \ km/h}}$

Explanation:

Distance between home & supermarket ($\rm d$) = 1 km

Time taken to walk from home to supermarket ($\rm t_1$) = 0.4 hours

Time taken to walk from supermarket to home ($\rm t_2$) = 0.6 hours

Total distance covered by man = Distance from home to supermarket + Distance from supermarket to home

= d + d

= 2d

= 2 km

Total time taken = $\rm t_1 + t_2$

= 0.4 + 0.6

= 1 hour

Formula:

$\boxed{ \bold{Average \ velocity \: (v_{avg}) = \frac{Total \ distance \ travelled}{Total \ time \ taken}}}$

By substituting values in the formula we get:

$\rm \implies v_{avg} = \dfrac{2}{1} \\ \\ \rm \implies v_{avg} = 2 \: km {h}^{ - 1}$

Answer 2

Answer:

= 1 hour  2 km

Explanation: