Question

a person walks from place A to place B with uniform speed of 10 m/s and travels back from place B to place A with uniform speed of 25 m/s calculate the average speed of the body for the whole journey​

Answer 1

Explanation:

Given:initial point to final point = 10m/s

Final to initial = 25m/s

Therefore average speed = 25-10

=15m/s

Sorry if it is wrong ok

Answer 2

Answer :

Let distance between A and B be d$.$

★ Case - I :

Distance travelled = d

Speed of person = 10m/s

Time taken to reach at B = d/10

★ Case - II :

Distance travelled = d

Speed of person = 25m/s

Time taken to reach at A = d/25

⧪ Average speed is defined as the ratio of total distance travelled to the total time taken.

➤ Total distance = d + d = 2d

➤ Total time = d/10 + d/25 = 7d/50

Let's calculate average speed;

⭆ v = distance / time

⭆ v = 2d/(7d/50)

⭆ v = 100/7

⭆ v = 14.28m/s

Cheers!