A person wants to make three lengths out of a 91 cm long board. The second length is 3 cm more than the shortest length and the third length is twice its length. Find the possible length of that shortest board if the third piece is at least 5 cm more than the second.
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let the no be x = x+3 =91then solve these equation
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Tota length = 91 cm
Let shortest length = a cm
Second length = a + 3 cm
Third length = 2a cm
Sum of length of boards ≤ 91 cm
a + (a + 3) + 2a ≤ 91
4a + 3 ≤ 91
4a ≤ 88
a ≤ 22 cm
Also third length =( a + 3) + 5 cm
2a ≥ ( a+3) + 5
2a≥ a + 8
a ≥ 8 cm
So, 8 ≤ a ≤ 22
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