a person was climbing on a building. he slip one for every 5 metre he climb up. if the building is 50 metre height and he takes 5 seconds to climb 1 metre .find the total time taken by him to get on the top of the buildings
Answers
Answered by
1
Answer: 312,5 sec (5,21min approx)
Step-by-step explanation:
He will climb 5m in 5*5 sec = 25 sec
Then he slips 1 m so in 25 sec he climbs 4 m.
It's a cross-multiplication: a/b = c/d ; ad = bc or a= (bc)/d
If 4m = 25 sec ; 1m = x sec
4x = 25; 1m = 25/4
50m = (25×50) ÷ 4 = 1250/4 = 312,5 sec (5,21min approx)
Similar questions