Question

A person watching through the window of an apartment sees a ball that rises vertically up and then vertically down for a total time of 0.5 seconds , if the height of the windows 2 metre then find the maximum height above the windows reached by the wall .

Answer 1

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Answer 2

The maximum height above the windows reached by the wall is 2.278 m.

Given the time of flight with respect to the window is 0.5sec .

Therefore ,

time taken to rise to the full height from the window is,

t = 0.25sec.

Let u be the velocity when it reaches the bottom of the window.

• Now s = ut + 0.5at^2

s = 2m == >

• 2 = 0.25 u  - 0.5x (10) x(0.25)^2

• 2 = 0.25u  - 0.3125 ==>

• u = 9.25m/s

Maximum height with this velocity is ,

• h = u^2/2g = 9.25^2/20 = 4.278 m

Therefore maximum height above the window is 4.278 - 2 = 2.278 m