A person weighing 55 kg walks by applying 160 N of force on the ground, while
pushing a 10-kg object. If the person accelerates at 2 m/s2
, what is the force of friction
experienced by the system consisting of the person and the object?
Answers
Answer:
case study A was a managing director of the company. his appointment condition was that he shall not, that it is the company not him who enticing the customer. decide if he and his company are one and the same
case study A was a case study A was a managing director of the company. his appointment condition was that he shall not entice the customer of the company during his employment or afterwards. his employment was terminated and after sometimes he formed a company to carry his own business that enticed the customer. he wanted to see the separate entity protection, that it is the company not him who enticing the customer. decide if he and his company are one and the same director of the company. his appointment condition was that he shall not entice the customer of the company during his employment or afterwar
Given:
Weight of person = 55Kg
Force applied by person on ground = 160N
Weight of object = 10Kg
Acceleration of person = 2m/s^2
To Find:
Force of friction experienced by the system
Solution:
F net on system = net mass of system x acc
or F= (55+10) x 2 N
F= 130N
F net = F applied by man - Frictional Force
or Frictional force =160-130= 30N
Hence, the force of friction experienced by the system is 30 N.