Question

A person weighing 55 kg walks by applying 160 N of force on the ground, while pushing a 10-kg object. If the person accelerates at 2 m/(s)^2, what is the force of friction experienced by the system consisting of the person and the object? *

Answer 1

GIVEN:

Weight of the person is 55 kg

Force applied on the ground is 160N

Weight of the object is 10 kg

Acceleration of the person is 2 $m/s^{2}$

TO FIND:

Force of the friction experienced by the system consisting of the person and the object.

SOLUTION:

Net Frictional Force on the system(F)=mass of the system × acceleration

F=(55+10)×2

   =130N

   N means units of the force

  Frictional forcce applied by the system=force applied by the man- force on the system

       =160-130

       =30N

FORCE OF THE FRICTION EXPERIENCED BY THE SYSTEM CONSISTING OF THE PERSON AND THE OBJECT IS  30N

 

Answer 2

GIVEN:

Weight of the person = 55 kg

Force applied on the ground = 160N

Weight of the object = 10 kg

Acceleration of the person = $2m/ {s}^{2}$

TO FIND:

Force of the friction experienced by the system consisting of the person and the object.

SOLUTION:

Net Frictional Force on the system(F)=mass of the system × acceleration

F=(55+10)×2

=130N

N means units of the force Newton

Frictional forcce applied by the system=force applied by the man- force on the system

=160-130

=30N

FORCE OF THE FRICTION EXPERIENCED BY THE SYSTEM CONSISTING OF THE PERSON AND THE OBJECT IS 30N