Question

A person weighing 56 kg is standing in a lift. Find the weight as recorded by the weighing machine when ( a) lift moves upward with acceleration of 2.1 m/s^2 (b) moves down with constant velocity of 2.1 m/s, given g= 9.8m/s^2.
only answer with process no bakwash​

Answer 1

Answer:

Mass of the man  m=40kg

Acceleration of lift in upward direction a=2m/s2

Let the weight shown by machine be N.

Equation of motion for the body :   ma=N−mg

We get  N=m(a+g)    

∴  N=(40)(2+10)=480  N

Thus weight of the man recorded by machine W′=gN

∴  W′=10480=48 kg



Explanation:

this will help you

Answer 2

Answer:

person weighing =56 kg

g=9.8m/s^2

wight=56×9.8 =548.8n(niuton)