Question

A person weighs 11 0.84 Newton on moon whose acceleration due to gravity is 1 / 6 of that of Earth if the value of g on earth is 9.8 m/s calculate (a)g on moon (b) mass of a person on moon (c) weight of person on earth

Answer 1

a) Value of g on moon = 1/6 × 9.8

                                      =1.63

b) W = mg

   110.84 = m × 1.63

   m = 110.84/1.63

   m = 68

c) W = mg

   W = 68 × 9.8

   W = 666.4

Answer 2

Given that,

Weight of the person, W = 110.84 N

Acceleration due to gravity on Moon is 1 / 6 of that of Earth.

Solution,

(a) Let $g_m$ is g on moon. So,

$g_m=\dfrac{1}{6}\times g_e\\\\g_m=\dfrac{1}{6}\times 9.8\\\\g_m=1.64\ m/s^2$

(b) The mass of the person is given by :

$W=m\times g_m\\\\m=\dfrac{W}{g_m}\\\\m=\dfrac{110.84}{1.64}\\\\m=67.58\ kg$

(c) Weight of the person on Earth is :

$W=mg_e\\\\W=67.58\times 9.8\\W=662.28\ N$

Hence, this is the required solution.

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