Question

A person weighs 60 kg .The area under one foot of person is 180cm sq. Find the pressure exerted on the ground by the person.

Answer 1

try
mass(m)=60 kg
area occupied (a)= 180*2 Cm.sq
= 360 cm.sq
= 360/100*100 m.sq
=0.04
pressure(p)=f/a
= m*g/a
= 60*9.8/0=0.04
= 588/0.04
= 14700
therefore pressure exerted by person is 14700 pa
(if wrong plz do it for me)

Answer 2

Pressure = force / area 

P = F/A 

Area under one foot = 180 cm² = 180 /100 x 100 m ²
 Area under two foot   = 2 x 180/100 x 100 = 0.36 m²

Force = mass x acceleration 

Here F = mg 
where g - acceleration due to gravity 

So pressure = Force / area 

P = F/A 

P = mg/A

P = 60 x 9.8 / 0.36 

P = 1366.3 Pa