A person weighs 80 kg.The area under one foot of the person is 180cm2.find the average pressure excerted on the ground by the person.
Answers
Answered by
1
mass = 80kg
weight = 80× 9.8 = 784N
area of 1 foot = 180 cm2
area of 2 feet = 180×2= 360 cm2 = 0.036 m2
Average pressure = weight/area = 784N/ 0.036 m2 =784000/36 Pa
You calculate it.
weight = 80× 9.8 = 784N
area of 1 foot = 180 cm2
area of 2 feet = 180×2= 360 cm2 = 0.036 m2
Average pressure = weight/area = 784N/ 0.036 m2 =784000/36 Pa
You calculate it.
Similar questions