Question

A person who along the boundary of a square Park of side 10 m in 40 seconds what will be the magnitude of displacement of the person at the end of 3 minutes..

Answer 1

Time= 180 secs
No. Of rounds = 180/40=3rounds
Net displacement =zero

Answer 2

man will move 4 full & 1 half cycle of square so for full cycle displacement will be zero .
so resultent displacement will be equal to displacement of half cycle .
net displacement will be
$10 \sqrt{2 =} 14.14$