a person who is suffered from near sighted Ness his far point at the distance of 80cm. how to correct it, which lens is used and find the power of lens.
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Answered by
1
concave lens , Power is 0.01 D
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Aasthakatheriya1:
hey !!!! dear for power change ur unit cm to m
oh ya , ty.
welcome
Answered by
2
heya freind!!!!!......
The person is suffering from myopia defect of vision . In this case , image is form before retina ,not on the retina .
◆ concave lens is used to correct this vision ...
u = infinity .
v = -80 cm ( far point ) .
⬇️By using lens formula!!!!!
--–--------------------
1/f = 1/v - 1/u .
1/f = 1/ (-80) - 0 .
1/f = 1/-80 .
f = -80 cm.
f = -0.8m .
⬇️now , ----------------------
p= 1/f .
p = -1.25 D ...
I hope it help you........
The person is suffering from myopia defect of vision . In this case , image is form before retina ,not on the retina .
◆ concave lens is used to correct this vision ...
u = infinity .
v = -80 cm ( far point ) .
⬇️By using lens formula!!!!!
--–--------------------
1/f = 1/v - 1/u .
1/f = 1/ (-80) - 0 .
1/f = 1/-80 .
f = -80 cm.
f = -0.8m .
⬇️now , ----------------------
p= 1/f .
p = -1.25 D ...
I hope it help you........
ur welcome dear
123 sona which ans is correct
which picture
My answer is wronf anyway
yaa i also think that alagar ans is wrong
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