Question

A person whose mass is 50 kg (weight about 500 N) has a surface area on one foot of 0.01 square metres. What pressure does the person exert on the ground if standing on both legs?

Answer 1

Answer:

Given:

Force exerted = 500N

Surface area of 1 foot = 0.01 m²

To find:

Pressure exerted on ground provided the man is standing on both feet

Concept:

Pressure is the ratio of force exerted to the area over which the force acts.

Frankly speaking , the force exerted is more appropriately called as Thrust . Thrust is perpendicular to the surface .

Calculation:

Area of 1 foot = 0.01 m²

Therefore area of 2 feet = 2 × 0.01 = 0.02 m²

Therefore ;

$pressure = \dfrac{force}{area}$

$= > pressure = \dfrac{500}{0.02}$

$= > pressure = 25000 \: pascal$

$= > pressure = 25 \: kilopascal$

So final answer :

$\boxed{ \sf{ \large{ \green{ \bold{pressure = 25 \: kilopascal}}}}}$

Answer 2

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Question :

A person whose mass is 50 kg (weight about 500 N) has a surface area on one foot of 0.01 square metres. What pressure does the person exert on the ground if standing on both legs?

Solution :

We Know That :

$</p><p>\tt{\red{Pressure = \dfrac{Force}{Area} = \dfrac{500}{0.2} = 25 \: Kpascal}}$