A person with a defective I is unable to see the objects nearer than 2 m he wants to read a book at a distance of 30 cm find the focal length
agrawalupanshu:
Nice
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it is hypermetropia
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The defect is hypermetropia
1/F=1/v-1/u
1/F=1/30-1/200
1/F= 200- 30 /6000
1/F= 170/6000....... 17/600=1/f
F=600/17
F= 35.29 CM
F=0.35 m
1/F=1/v-1/u
1/F=1/30-1/200
1/F= 200- 30 /6000
1/F= 170/6000....... 17/600=1/f
F=600/17
F= 35.29 CM
F=0.35 m
Thanks
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