Question

A person x sets out awalk from a to b at the same time another person y starts walk from b to a. After passing each other x and y complete journys in 3hours20minuts and 4hours48minuts respectively.If x walk at the speed of 4.5 ,what is the speed of yKm/hr?

Answer 1

Hi there!
Here's the answer:

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$Velocity\: v = \frac{Distance\: d}{Time\: t}$

=> $Distance = Velocity × Time$

Given,
Distance covered by x = distance covered by y
=> $d_{x} = d_{y}$

We have,
$d_{x} = v_{x}t_{x}$ -------(1)
$d_{y} = v_{y}t_{y}$ -------(2)

Equate(1) & (2)

$v_{x}t_{x} = v_{y}t_{y}$ -------(2)

=> $v_{y} = \frac{v_{y}t_{y}}{t_{y}}$

$t_{x} = 3Hrs\: 20 min$
=>3 + $(\frac{20}{60}) = 0.33 Hrs$

$t_{y} = 4Hrs\: 48 min$
=>4 + $(\frac{20}{60}) = 4.8 Hrs$

Substitute values in $v_{y}$

=> $v_{y} = \frac{3.33×4.5}{4.8}$

=> $v_{y} = \frac{14.99}{4.8}$

•°• $v_{y} = 3.12 km$

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