A Person X started at 3 hours earlier at 40km/h from a place P, then another person Y followed him at 60km/h. Started his journey at 3 O'clock, afternoon. What is the diference in time when X was30 km ahead of Y and when Y was 30 km ahead of X?
A) 2h
B) 3h
C) 3.5h
D) 4.25h
Answers
Step-by-step explanation:
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Secondary School Math 13 points
A person x started at 3 hours earlier at 40km/h from a place p, then another person y followed him at 60km/h. Started his journey at 3 o'clock, afternoon. What is the diference in time when x was30 km ahead of y and when y was 30 km ahead of x?
Ask for details Follow Report by JaidKamar4936 20.04.2019
Answers
qwpenguin Ace
Answer:
3 hrs
Step-by-step explanation:
Distance = 40km/h
Time = -3hrs
Distance of y = 60km/h
Time of y = 3pm
Time as to when X was 30 km ahead of Y
= (120-30)/20
=4.5h
Time as to when Y was 30 km ahead of X
= (120+30)/20
= 7.5 h
Thus, the required difference in time = 7.5-4.5 = 3
Therefore, the diference in time when x was30 km ahead of y and when y was 30 km ahead of x will be 3 hrs