Question

. A petrol tank is already (2/3)rd filled. When 8 litre is added it is filled by (5/6)th of the tank. Find the tank capacity.

Answer 1

Step-by-step explanation:

Let the tank capacity be x litres.

Hence,

$\frac{2}{3} x + 8 = \frac{5}{6} x \\ \frac{5}{6} x- \frac{2}{3} x = 8 \\ \frac{5}{6} x - \frac{2 \times 2}{3 \times 2} x = 8 \\ \frac{5}{6} x - \frac{4}{6} x = 8 \\ \frac{5x - 4x}{6} = 8 \\ \frac{x}{6} = 8 \\ x = 6 \times 8 \\ x = 48 \\ \therefore \: tank \: capacity \: is \: 48 \: litres.$

Answer 2

Step-by-step explanation:

Let the total capacity of the tank is =x litre

Now,

tank is already (2/3)rd filled. When 8 litre is added it is filled by (5/6)th of the tank. Find the tank capacity.

So, according to the problem... The equation is...

$8 + \frac{2x}{3} = \frac{5x}{6} \\ = > 8 = \frac{5x}{6} - \frac{2x}{3 } \\ = > 8 = \frac{ 5x - 4x}{6} \\ = > 48 = x \\ = > x = 48$

Therefore the total capacity is =48 litres