Math, asked by prayasharma, 1 year ago

A petrol tank is in the form of a frustum of a cone of height 20 m with diameters of its

lower and upper ends as 20 m and 50 m respectively. Find the cost of petrol which can

fill the tank completely at the rate of Rs. 70 per litre. Also find the surface area of the

tank​

Answers

Answered by haridasan85
3

Vol of frustum= πh/3(R2+ r2+Rr)

3.14x20/3(25^2+10^2+25x10)

=20410m3

=20410000 litre

cost of petrol =20410000x70

= Rs142,87,00,000

Area of slant surface=π(R+ r)s

s=vh 2+(R-r) 2

=v 20 ^2+ (25-10)^2

=v4oo+225=v625=25m

Area of slant surface-

= π(R+r)s

3.14x(25 +10) 25

3.14x35x25=2747.50 m2

π(R+ r)s

s=vh^2+(R-r) 2)

Answered by alokdesai2004
5

Answer:

Step-by-step explanation:

h = 20m

R = 25m

r = 10m

l = ✓h^2 + (R-r)^2 = ✓625 = 25m

For Volume -

1/3πh(R^2+r^2+R-r)

= 1/3×22/7×20×975

= 143000/7m^3

1m^3 = 1000l

Cost =

143000/7×70×1000

= 1430000000Rs

SA = CSA + Area of Base

= π(R+r)l + πr^2

= 22/7(35)25 + 22/7×100

= 2750 + 314.28

= approx. 3064.28m^2

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