A petrol tank is in the form of a frustum of a cone of height 20 m with diameters of its
lower and upper ends as 20 m and 50 m respectively. Find the cost of petrol which can
fill the tank completely at the rate of Rs. 70 per litre. Also find the surface area of the
tank
Answers
Answered by
3
Vol of frustum= πh/3(R2+ r2+Rr)
3.14x20/3(25^2+10^2+25x10)
=20410m3
=20410000 litre
cost of petrol =20410000x70
= Rs142,87,00,000
Area of slant surface=π(R+ r)s
s=vh 2+(R-r) 2
=v 20 ^2+ (25-10)^2
=v4oo+225=v625=25m
Area of slant surface-
= π(R+r)s
3.14x(25 +10) 25
3.14x35x25=2747.50 m2
π(R+ r)s
s=vh^2+(R-r) 2)
Answered by
5
Answer:
Step-by-step explanation:
h = 20m
R = 25m
r = 10m
l = ✓h^2 + (R-r)^2 = ✓625 = 25m
For Volume -
1/3πh(R^2+r^2+R-r)
= 1/3×22/7×20×975
= 143000/7m^3
1m^3 = 1000l
Cost =
143000/7×70×1000
= 1430000000Rs
SA = CSA + Area of Base
= π(R+r)l + πr^2
= 22/7(35)25 + 22/7×100
= 2750 + 314.28
= approx. 3064.28m^2
1
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