Question

a petrol tank is in the from of cylinder whous radius is 1.5cm and length is 7m find the quantity of petrol in litters that can be stored in the tank​

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt A\: petrol\: tank \:is\: in\: the\: from\: of\: cylinder\: whose\: radius\\\tt is \:1.5\:cm\: and\: length\: is\: 7\:m\: find\: the \:quantity\: of\\\tt petrol\: in \:litters\: that \:can \:be \:stored\: in\: the\: tank$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\bf Radius \:of \:the \:cylinder =1.5\:cm$
• $\bf Height \:of \:the \:cylinder =7\:m$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\bf The\: quantity\: of\: petrol\: that\: can\: be\: stored\: in\:the\: tank$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\pink {\underline {\bf {\pmb {Converting \:centi-metres(cm)\:into\:meter(m)}}}}}$

${\blue {\boxed {\boxed {\boxed {\green {\pmb {100\:cm=1\:m}}}}}}}$

${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$

$\bf\implies m=\dfrac{1.5}{100}$

$\implies {\blue {\boxed {\boxed {\purple {\sf {m=0.015}}}}}}$

—————————————————————————————

${\pink {\underline {\bf {\pmb {Volume \:of \:the \:tank}}}}}$

${\blue {\boxed {\boxed {\boxed {\green {\pmb {V_{(Cylinder)}=\pi{r}^{2}h}}}}}}}$

• $\sf V=volume \:of \:the \:cylinder$
• $\sf r=radius\:of \:the \:cylinder$
• $\sf h=height\:of \:the \:cylinder$

${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$

$\bf \implies V=\dfrac{22}{7}\times {\Big(0.015\Big)}^{2}\times 7$

$\bf \implies V=\dfrac{22}{7}\times 0.000225 \times 7$

$\bf \implies V=\dfrac{22}{\cancel{7}}\times 0.000225\times \cancel{7}$

$\bf \implies V=22\times 0.000225$

$\implies {\blue {\boxed {\boxed {\purple {\sf {V=0.00495\:{cm}^{3}}}}}}}$

—————————————————————————————

${\pink {\underline {\bf {\pmb {Quantity \:of \:the \:petrol\:that\:can\:be\:stored \:in\:tank}}}}}$

${\blue {\boxed {\boxed {\boxed {\green {\pmb {1\:{cm}^{3}=1000\:l}}}}}}}$

${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$

$\bf\implies l=0.00495\times 1000$

$\implies {\blue {\boxed {\boxed {\purple {\mathfrak {l=4.95}}}}}}$

${\underbrace {\red {\overline {\red {\underline {\red {\sf {\pmb {{\therefore}\:\: 4.95\:litres \:of\:petrol\:can\:be\:stored \:in\:that\:tank}}}}}}}}}$

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$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\sf Curved \:surface \:area \:of \:the \:cylinder =2\pi rh$

$\sf Total\:surface \:area \:of \:the \:cylinder =2\pi r(r+h)$

$\sf Volume \:of \:the \:cylinder =\pi{r}^{2}h$