A pharmacist needs to strength a 15% alcohol solution to one of 32% alcohol. How much pure alcohol should be added to800ml of 15% solution?
aaryan27:
please tell how u add 200 ml
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32/100×1000.
so answer is 200...
Hope u understand.
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so answer is 200...
Hope u understand.
Please follow me
Please mark as Brainliest answer.
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Answered by
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Answer :
- Quantity of pure alcohol added to 15 % solution to get 32% solution = 200 ml.
Given :
- A pharmacist needs to strength a 15% alcohol solution to one of 32% alcohol.
To find :
- How much pure alcohol should be added to 800ml of 15% solution = ?
Step-by-step explanation :
Quantity of pure alcohol in 400 ml of 15 % solution = 800 × 15/100 = 120 ml
Let pure alcohol added to 15 % solution to get 32% solution = x ml.
Then quantity of pure alcohol = (60 + x) ml
According to the given question, we have
120 + x = 32% of (800 + x) = 32/100(800 + x)
⟹ 120 + x = 8/25(800 + x)
⟹ 25(120 + x) = 8(800 + x)
⟹ 3000 + 25x = 6400 + 8x
⟹ 25x - 8x = 6400 - 3000
⟹ 17x = 3400
∴ x = 3400/17 = 200.
Hence, quantity of pure alcohol added to 15 % solution to get 32% solution = 200 ml.
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