Math, asked by payal63, 1 year ago

A pharmacist needs to strength a 15% alcohol solution to one of 32% alcohol. How much pure alcohol should be added to800ml of 15% solution?


aaryan27: please tell how u add 200 ml
harshsingh1331p5fs2b: How you add 200ml

Answers

Answered by Anonymous
5
32/100×1000.

so answer is 200...

Hope u understand.

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utkarsh46: ur answer method is also right but my method is unique
payal63: Your writing is gud
payal63: Yash
aaryan27: how did u add 200 how do we know we had to add 200 we can 500 ,600 any thing can be there. give the right explanation
aaryan27: how 200 ml is added
Answered by BrainlyRaaz
5

Answer :

  • Quantity of pure alcohol added to 15 % solution to get 32% solution = 200 ml.

Given :

  • A pharmacist needs to strength a 15% alcohol solution to one of 32% alcohol.

To find :

  • How much pure alcohol should be added to 800ml of 15% solution = ?

Step-by-step explanation :

Quantity of pure alcohol in 400 ml of 15 % solution = 800 × 15/100 = 120 ml

Let pure alcohol added to 15 % solution to get 32% solution = x ml.

Then quantity of pure alcohol = (60 + x) ml

According to the given question, we have

120 + x = 32% of (800 + x) = 32/100(800 + x)

⟹ 120 + x = 8/25(800 + x)

⟹ 25(120 + x) = 8(800 + x)

⟹ 3000 + 25x = 6400 + 8x

⟹ 25x - 8x = 6400 - 3000

⟹ 17x = 3400

∴ x = 3400/17 = 200.

Hence, quantity of pure alcohol added to 15 % solution to get 32% solution = 200 ml.

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