Math, asked by sinju678nimna, 1 year ago

A pharmacist needs to strengthen a 15% alcohol solution
to one of 32% alcohol.How much pure alcohol should be added to 800 ml of 15% solution?

Answers

Answered by Yashwant216
6
Add 200ml of pure alcohol

sinju678nimna: How...Explain
Yashwant216: Let us say we need to add x ml in it to make it 32% so
Yashwant216: (X+120/800+X) 100=32 then solve for x
jmansi829priyanshu: Explain properly
chiku88: full ans
Answered by tardymanchester
5

Answer:

Required amount is 160 ml.

Step-by-step explanation:

Given : A pharmacist needs to strengthen a 15% alcohol solution to one of 32% alcohol.

To find : How much pure alcohol should be added to 800 ml of 15% solution?

Solution :

Let x be the amount of pure alcohol.

15% alcohol solution    

Amount of active ingredient = 0.15x ml

Pure alcohol is 800 ml added

So, Amount of active is 800-x ml

32% solution of alcohol:

Amount of active is 0.32\times 800 = 256 ml

The required equation is,

0.15x + 800-x = 256

 0.85x =544

 x =640

Amount of pure alcohol needed for the solution is

800-x =800-640= 160 ml

Therefore, Required amount is 160 ml.

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