Question

A phone cost rupees 8,350 and decreases in value by 12% per year. How much will the phone be worth in 5 years?

Answer 1

Answer:

₹4,406.56

Step-by-step explanation:

In order to find the answer for this problem, we would need to decrease the valuer of the phone 5 times (that would be equivalent to 5 years)

We would get the value of the phone (cost) of ₹8,350 and multiply it by 12, then subtract the percentage from the value. That's the long way, but I have a shorter way for you.

We would be using this equation:

$\mathrm{p}(1 - \mathrm{x})^\mathrm{y}$

• $\mathrm{p}$ = Principal or Starting Value
• $\mathrm{x}$ = Percentage
• $\mathrm{y}$ = Amount of years

Now, we plug in the given information from the question into the equation. Your equation should look like this:

$8,350(1-0.12)^5$

Now solve it.

When you're done solving, you should get ₹4,406.56

The phone would be worth ₹4,406.56 in 5 years after a 12% decrease each year.

Answer 2

the answer to your question is :

cost of phone : Rs. 8,350         (PRINCIPLE)

decrease percent : 12%            (RATE)

time period : 5 Years                (n or TIME PERIOD)

now we use amount formula that is used in compound interest i.e:

Amount = Principle( 1 + r/100)^{time period}

but instead of doing 1 + r/100 we do 1 - r/100

so,

amount = 8350( 1 - 12/100 )^5

             = 8350( 100/100 - 12/100)^5

             = 8350( 88/100 )^5

             = 8350×88/100×88/100×88/100×88/100×88/100

             = 8350×0.88×0.88×0.88×0.88×0.88

             = Rs.4406.56

price of the phone after 5 years = original price - amount

                                                      = 8350 - 4406.56

                                                      = Rs.3943.44

∴ The price of the phone after ten years is Rs.3,943.44.

Hope you find it helpful! Have a nice day!

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