Math, asked by shivarthagrawal, 2 months ago

A photo frame of dimensions 48 cm by 32 cm has a border of width 5 cm around and inside it. Find the
cost of decorating the border at the rate of 5.25 per sq. em and also find the area of the photo that can
be fit in the frame.​

Answers

Answered by zarathequeen
14

Step-by-step explanation:

Difference of two rectangles, one being an external rectangle and the other an internal.

Area of external rectangle = length*breadth = 40cm*30cm = 1200cm square

Area of internal rectangle:

length= 40cm - 2(5cm) = 30 cm

breadth = 30 cm - 2(5cm) = 20 cm

Area = length*breadth = 30cm*20cm = 600 cm square

Area of the border = Area of external rectangle - Area of internal rectangle

= 1200 cm square - 600 cm square

= 600 cm. square

Answered by arjunjayakumar09
1

Answer:

Step-by-step explanation:

Difference of two rectangles, one being an external rectangle and the other an internal.

Area of external rectangle = length*breadth = 40cm*30cm = 1200cm square

Area of internal rectangle:

length= 40cm - 2(5cm) = 30 cm

breadth = 30 cm - 2(5cm) = 20 cm

Area = length*breadth = 30cm*20cm = 600 cm square

Area of the border = Area of external rectangle - Area of internal rectangle

= 1200 cm square - 600 cm square

= 600 cm. square

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