a photo measuring 7.5 CM by 5 cm and is enlarged, so that the largest side becomes 18cm what does the shorter side become? in what ratio is the area increased?
Answers
Answer:
The length of the shorter side is 12 cm and the ratio area increased by 5.76 : 1.
Step-by-step explanation:
Consider the provided information.
The area of rectangle is = a × b, where a and b are the sides.
A photo measuring 7.5 CM by 5 cm
The area of the photo is:
7.5 × 5 = 37.5 cm²
Let x be the constant ratio
Ratio of Length : Width = 7.5x : 5x
Now the area of the largest side becomes 18cm.
7.5x = 18
x = 18/7.5
x = 2.4
Thus the width is 5x = 5 × 2.4 = 12 cm
The new length and width is 18 cm and 12 cm respectively.
Now the new area is: 18 × 12 = 216 cm²
The ratio of area increase is 216 : 37.5 which is also equals to 5.76 : 1.
Answer:
Answer is 12&5.76:1
Step-by-step explanation:
Area of photo=7.5*5=37.5
7.5x=18
X =2.4
5x=5*2.4=12
New area =18*12=216sq.cm
Ratio=216*10/37.5=5.76:1