A photo measuring 7.5 cm by 5 cm is enlarged ,so that the larger side becomes 18 cm .what does the shorter side become?in what ratio is the area increased...
Answers
Answer: The length of the shorter side is 12 cm and the ratio area increased by 5.76 : 1.
u looking pretty sis
^_^
Answer:
The length of the shorter side is 12 cm
and the ratio area increased by 5.76 : 1.
Explanation:
The length of the shorter side is 12 cm
and the ratio area increased by 5.76 : 1.
Step-by-step explanation:
Consider the provided information.
The area of rectangle is = a x b, where a
and b are the sides.
A photo measuring 7.5 CM by 5 cm
The area of the photo is:
7.5 x 5 = 37.5 cm?
Let x be the constant ratio
Ratio of Length : Width = 7.5x : 5x
Now the area of the largest side
becomes 18cm.
7.5x = 18
x = 18/7.5
x = 2.4
Thus the width is 5x = 5 x 2.4 = 12 cm
The new length and width is 18 cm and
12 cm respectively.
Now the new area is: 18 x 12 = 216 cm?
The ratio of area increase is 216 :37.5
which is also equals to 5.76:1.