Question

A photocell in the saturation mode is irradiated by light of wavelength = 6600 Å. The corresponding spectral sensitivity of the cell is 4.8 mA/W. Find the yield of photoelectrons, i.e. the number of photoelectrons produced by each incident photon. [Take : h = 6.6 × 10^-34 J.s]

a. 9×10^-2
b. 9×10^-4
c. 9×10^-3
d. 9

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Answer 1

Answer:

Correct option is C

9×10 raised to -3

 

Let n  

e

​

 be the number of electrons, and n  

p

​

 be the number of photons.

Thus s  

λ

​

=  

n  

p

​

hc

n  

e

​

eλ

​

 

⟹  

n  

p

​

 

n  

e

​

 

​

=  

eλ

s  

λ

​

hc

​

=9×10  

−3

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