a photograph measuring 7.5 cm by 6.5 cm is to be enlarged. If the enlargement of the longest side is 18cm, then the length of the smaller side is:
Answers
Answer:
the length of the shorter side is 12 cm an the ratio area increased by 5.76:1.
Step-by-step explanation:
conside the provided information.
the area of rectangle is = a × b, where a and b are the sides.
a photo measuring 7.5cm by 5cm
the area of the photo is :
7.5 × 5= 37.5cm^2
let x be the constant ratio
Ratio of length : Width= 7.5x : 5x
Now the area of the largest side
becomes 18cm.
7.5x = 18
x = 18/7.5
x = 2.4
thus the width is 5x = 5 × 2.4 = 12cm.
the new length and width is 18 cm and 12 cm respectively.
now the new area is: 18 × 12 = 216 cm^2
The ratio of area increase is 216 : 37.5
which is also equals to 5.76 : 1.
The length of smaller side of photograph would be 15.6 cm.
A photograph measuring 7.5 cm × 6.5 cm is to be enlarged. if the enlargement of the longest side is 18cm.
We have to find the length of the smaller side.
Here resolution of photograph is 7.5 cm × 6.5 cm
means, the ratio of the length and breadth = 7.5 cm : 6.5 cm = 15 : 13
Let the proportionality constant is x.
The length of longer side = 15x = 18 cm [Given]
⇒ x = 18/15 = 1.2
And the length of smaller side = 13x = 13 × 1.2 = 15.6 cm
Therefore the length of smaller side of photograph would be 15.6 cm.
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