Math, asked by nirmalaravi4344, 3 months ago

a photograph measuring 7.5 cm by 6.5 cm is to be enlarged. If the enlargement of the longest side is 18cm, then the length of the smaller side is:​

Answers

Answered by dollybakshi2007
13

Answer:

the length of the shorter side is 12 cm an the ratio area increased by 5.76:1.

Step-by-step explanation:

conside the provided information.

the area of rectangle is = a × b, where a and b are the sides.

a photo measuring 7.5cm by 5cm

the area of the photo is :

7.5 × 5= 37.5cm^2

let x be the constant ratio

Ratio of length : Width= 7.5x : 5x

Now the area of the largest side

becomes 18cm.

7.5x = 18

x = 18/7.5

x = 2.4

thus the width is 5x = 5 × 2.4 = 12cm.

the new length and width is 18 cm and 12 cm respectively.

now the new area is: 18 × 12 = 216 cm^2

The ratio of area increase is 216 : 37.5

which is also equals to 5.76 : 1.

Answered by abhi178
2

The length of smaller side of photograph would be 15.6 cm.

A photograph measuring 7.5 cm × 6.5 cm is to be enlarged. if the enlargement of the longest side is 18cm.

We have to find the length of the smaller side.

Here resolution of photograph is 7.5 cm × 6.5 cm

means, the ratio of the length and breadth = 7.5 cm : 6.5 cm = 15 : 13

Let the proportionality constant is x.

The length of longer side = 15x = 18 cm [Given]

⇒ x = 18/15 = 1.2

And the length of smaller side = 13x = 13 × 1.2 = 15.6 cm

Therefore the length of smaller side of photograph would be 15.6 cm.

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