Question

A photograph measuring 7.5 cm by
6.5 cm is to be enlarged. If the enlargement of the longest side is 18 cm then the length of smaller side in cm is​

Answer 1

Answer:

the length of the shorter side is 12 cm an the ratio area increased by 5.76:1.

Step-by-step explanation:

conside the provided information.

the area of rectangle is = a × b, where a and b are the sides.

a photo measuring 7.5cm by 5cm

the area of the photo is :

7.5 × 5= 37.5cm^2

let x be the constant ratio

Ratio of length : Width= 7.5x : 5x

Now the area of the largest side

becomes 18cm.

7.5x = 18

x = 18/7.5

x = 2.4

thus the width is 5x = 5 × 2.4 = 12cm.

the new length and width is 18 cm and 12 cm respectively.

now the new area is: 18 × 12 = 216 cm^2

The ratio of area increase is 216 : 37.5

which is also equals to 5.76 : 1.

Answer 2

Answer:

A photograph measuring 7.5 cm by 6.5 cm is to be enlarged. If the enlargement of the longest side is 18 cm.

Step-by-step explanation:

Here we have to increase the length of the smaller side in the same ratio of length : width of older measuring of photograph that is 7.5: 6.5

For that we have to assume,

Let $x$ be the constant ratio. Then ratio of length and width be $7.5x : 6.5x$ i.e $1.154:1$.

• If longest side is enlarged to $18cm$ then, shortest side will be

         width = $\frac{18}{1.154}$

         $=15.6cm$

Now length and width are in same ratio as older length and width.

Hence, length of the smaller side of the photograph will be 15.6 cm.

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