Math, asked by aklindramuz43, 11 months ago

a photograph of a bacteria enlarge 50000 times attains a length of 5 cm the actual length of bacteria is

Answers

Answered by vickysharma6287

Step-by-step explanation:

Answer: Given that a photograph of a bacteria enlarged 50,000 times attains a length of 5 cm. Therefore, the actual length of the bacteria is = (5/50000) cm = 0.0001 cm. If the photograph is enlarged 20,000 times only, then its enlarged length will be = (20000*0.0001) cm = 2 cm.

Answered by zakirhussain786

Answer:

that a photograph of a bacteria enlarged 50,000 times attains a length of 5 cm. Therefore, the actual length of the bacteria is = (5/50000) cm = 0.0001 cm. If the photograph is enlarged 20,000 times only, then its enlarged length will be = (20000*0.0001) cm = 2 cm.

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a photograph of a bacteria enlarge 50000 times attains a length of 5 cm the actual length of bacteria is ​

Answers

that a photograph of a bacteria enlarged 50,000 times attains a length of 5 cm. Therefore, the actual length of the bacteria is = (5/50000) cm = 0.0001 cm. If the photograph is enlarged 20,000 times only, then its enlarged length will be = (20000*0.0001) cm = 2 cm.

a photograph of a bacteria enlarge 50000 times attains a length of 5 cm the actual length of bacteria is