Question

A photograph of a bacteria enlarged 50000 times attains a length of 5 cm. What is the
actual length of the bacteria? If the photograph is enlarged 20000 times only, what
would be its enlarged length?​

Answer 1

Given that a photograph of a bacteria enlarged 50,000 times attains a length of 5 cm. Therefore, the actual length of the bacteria is = (5/50000)cm = 0.0001 cm. If the photograph is enlarged 20,000 times only, then its enlarged length will be = (20000*0.0001) cm = 2 cm.

Answer 2

$\bigstar$ Given:

• Length of a photograph of a bacteria enlarged 50000 times = 5 cm

$\bigstar$ To Find:

• Enlarged length of the photograph if it is enlarged 20000 times.

$\bigstar$ Solution:

Let enlarged length of bacteria be x

Actual length of bacteria = $\frac{5}{50000} = \frac{1}{10000} \: cm= 10^{-4} \: cm$

Here, length and enlarged length of bacteria are in direct proportion

$\frac{5}{50000} = \frac{x}{20000}$

$\implies x=50000=5 \times 20000$

Value of x,

$x= \frac{5 \times 20000}{50000}$

$x=\boxed{\underline{\underline{2 \: cm}}}$

Hence, the enlarged length of bacteria is 2 cm