A photographer of a bacteria enlarged 50000 times attains a length of 5cm. what is actual length of the bacter? if the photographer is enlarged 20000 times only what would be its enlarged length.
Answers
If two quantities increase or decrease together in such a
manner that the ratio of their corresponding values remain constant, we say that the two quantities vary directly.
In other words x and y are said to vary directly if X/y = k
, where k is a positive constant.
In direct Proportion
x/y= k
x=ky
So we can find value of k from known values, and then use the
formula to calculate the unknown values.
When two quantities x and y are in direct proportion (or vary directly) they are
also written as x∝y.
=========================================================
Solution:
[Table is in the attachment]
Let the actual length of bacteria be ‘x’
& enlarged length be y cm.
Here the number of times the photograph of bacteria was enlarged & the length of the bacteria are in direct
proportion.
5/50000=x /1
X= 1/10000
x=0.0001cm
x=10^-4
Hence, the actual length of bacteria is
10^-4
Let the length of the bacteria when the
photograph of bacteria was enlarged 20000 times be y
5/50000 = y/20000
y × 50000 = 5× 20000
y= 5× 20000/50000
y= 2cm.
Hence, the enlarged length of the bacteria
is 2cm.
50,000 times----------------->5 cm
1 time----------------------------->5/50,000=1/10,000(ACTUAL LENGTH)
20,000 times------------------>20,000/10,000
=2 cm
HOPE THIS HELPS!!!!!!!!!