Math, asked by yadav1492, 1 year ago

A photographer of a bacteria enlarged 50000 times attains a length of 5cm. what is actual length of the bacter? if the photographer is enlarged 20000 times only what would be its enlarged length.

Answers

Answered by Anonymous
11

If two quantities increase or decrease together in such a

manner that the ratio of their corresponding values remain constant, we say  that the two quantities vary  directly.


In other words x and y are said to vary directly if X/y = k

, where k is a positive constant.


In direct Proportion


x/y= k



x=ky


So we can find value of k from known values, and then use the

formula to calculate the unknown values.




When two quantities x and y are in direct proportion (or vary directly) they are

also written as x∝y.


=========================================================


Solution:


[Table is in the attachment]


Let the actual length of bacteria be ‘x’

& enlarged length be y cm.


Here the number of times  the photograph of bacteria was enlarged  & the length of the bacteria are in direct

proportion.


5/50000=x /1


X= 1/10000


x=0.0001cm 


 x=10^-4


Hence, the actual length of bacteria is

10^-4


 


Let the length of the bacteria when the

photograph of bacteria was enlarged 20000 times be y


5/50000 = y/20000


y × 50000 = 5× 20000


y= 5× 20000/50000


y= 2cm.


Hence, the enlarged length of the bacteria

is 2cm.




sahiljairamani785: hmm great answer mam!
Answered by bswagatam04
5

50,000 times----------------->5 cm


1 time----------------------------->5/50,000=1/10,000(ACTUAL LENGTH)


20,000 times------------------>20,000/10,000


                                          =2 cm


HOPE THIS HELPS!!!!!!!!!



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