Question

A photon beam of energy 12.1ev is incident on a hydrogen atom. The orbit to which electron of h-atom be excited is

Answer 1

Answer:

3rd orbit is the answer

Explanation:

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Answer 2

A photon beam of energy 12.1ev is incident on a hydrogen atom. The orbit to which electron of h-atom be excited is 3rd .

Explanation:

It is based on Bohr model postulate

1. We know that as long as electron remain in its own shell , it neither looses or gain energy by itself or we can say that energy of energy levels are fixed .
2. According to it , when energy is supplied to an electron , it gets excited to higher energy level .But higher energy level is always unstable .Therefore, the excited electron ultimately returns to its original level and while doins this , it emits the energy absorbed by it .
3. The emitted energy is actually a difference between energy of ground state and excited state .
4. This can be calculated as :

ΔE =  -13.6/n₂²-n₁²

We are given that : change in energy =12.1 eV

Initial orbit of electron in H atom =1

The orbit to which it gets excited =?

12.1 = -13.6/n₂²-1²

12.1+(-13.6)

n₂²= -13.6 /-1.5=9

n²₂=9

or n₂=3

The orbit to which electron of h-atom be excited is 3rd .

12.1 = 967500(1/1²-1/n₂)