Question

A photon beam of energy 12.1ev is incident on a hydrogen atom. The orbit to which electron of h-atom be excited is

Answer 1

Answer:

Explanation:

Energy of an electron in an orbit is given by the following formula

En = -13.6/n2 eV

where 'n' is the orbit number

So if we calculate the energy of the 3rd orbit election by the above-given formula it comes out to be 1.51 eV which is exactly equal to the sum of energy of electron in the first orbit and 12.1 eV absorbed by the electron.

So the electron will get excited to the 3rd orbit.